Question

Find the remainder on dividing 5y³ – 2y² – 7y –1 by y

Answer 1

Answer:

Let y = 0

$= 5 × 0³ - 2 × 0² - 7 × 0 - 1$

$= 0 - 0 - 0 - 1$

Therefore the remainder is 1

Step-by-step explanation:

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