Question

Find the remainder:p(y) = y
^3 – 4y^2
-2y + 6 and g(y) = 1 -
3/
4
y.​

Answer 1

p(y) = y^3 -4y^2 - 2y + 6

g(y) =1- 3y/4 = 0

= 1 = 3y/4

= 4/3 = y

by putting y value in p(y) we get our remainder

p(4/3)= (4/3)^3 - 4(4/3)^2 - 2(4/3) + 6

=64/27 - 64/9 - 8/3 +6

= (64 - 192 - 72 + 162)/27

= -39/27

= -13/9

hence remainder is. -13/9

Answer 2

Answer:

the answer provided contains the correct calculations and concept It is done by Remainder Theorem according to which

when polynomial p(x) having degree n >=1 is divided by x+ a where a is any real number then remainder is the value of p(-a)