find the remainder.
please also write the steps. don't give direct answer.
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Answered by
8
hiii!!!
here's ur answer...
the easy way to find the remainder is by remainder theorem.
given p(y) = 4y³ - 12y² + 5y - 4
g(y) = 2y - 1 = 0
2y = 1
y = 1/2
on putting values :-
p (1/2) = 4(1/2)³ - 12(1/2)² + 5(1/2) - 4
= 4(1/8) - 12(1/4) + 5/2 - 4
= 1/2 - 3 + 5/2 - 4
= 6/2 - 7
= 6/2 - 14/2
= -8/2
= -4
-4 is the remainder of the given equation.
hope this helps..!!
here's ur answer...
the easy way to find the remainder is by remainder theorem.
given p(y) = 4y³ - 12y² + 5y - 4
g(y) = 2y - 1 = 0
2y = 1
y = 1/2
on putting values :-
p (1/2) = 4(1/2)³ - 12(1/2)² + 5(1/2) - 4
= 4(1/8) - 12(1/4) + 5/2 - 4
= 1/2 - 3 + 5/2 - 4
= 6/2 - 7
= 6/2 - 14/2
= -8/2
= -4
-4 is the remainder of the given equation.
hope this helps..!!
Sahil1231:
thanks a lot
Answered by
2
remainder is -4
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