Find the remainder when 11^12-1 is divided by 133
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Answer:
remainder=2
Step-by-step explanation:
133/131=remainder=2
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(11^12) -1 divided by 133. REMAINDER obtained is 0
◆DIVIDEND×DIVISOR + REMAINDER = SUM
◆133 is the DIVISOR. Sum divided by DIVISOR gives you an integer (DIVIDEND) , the number which remains back gives you the REMAINDER.
◆(11^12) -1 divided by divisor 133.
●Solving further,
(11^12 ) -1 =11^12 - 1^12
=(11^6 +1)(11^6-1).
[as,x^2- y^2 =( x-y) (x+y)]
=3,138,428,376,720
◆This sum is completely divisible by 133, and gives dividend
24,141,756,744.
◆Thus, REMAINDER = 0
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