Question

find the remainder when 16 x cube minus 12 x square + 14 x minus 3 is divided by 2x - 1​

Answer 1

Answer:

Step-by-step explanation:

Given,

$f(x) = 16x^{3} - 12x^{2} + 14x - 3$

is to be divided by (2x-1)

thus 2x-1 = 0

        2x = 1

           x = $\frac{1}{2}$

Now let

$f(\frac{1}{2} ) = 16(\frac{1}{2} )^{3} - 12(\frac{1}{2} )^{2} + 14(\frac{1}{2} ) - 3$

on solving this we get

f(1/2) = 3