find the remainder when 2^100 is divided by 3 ???
Answers
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Method - 1:
We know that
= > 2 mod 3 = 2[2^1/3 = 2]
= > 4 mod 3 = 1[2^2/3 = 1]
= > 8 mod 3 = 2[2^3/3 = 2]
= > 16 mod 3 = 1[2^4/3 = 1]
= > 32 mod 3 = 2[2^5/3 = 2]
Now,
According to question.
= > 2^100/3
= > (2^4)^25/3
= > 1^25/3
= > 1.
Therefore, the remainder is 1.
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Method - 2:
Here, it should be in the form of a = b(mod n).
When a is divided by n, the remainder is b.
Now,
= > 2^2 = 1(mod 3)
= > (2^2)^5 = 1^5(mod 3)
= > (2^10) = 1(mod 3)
= > 2^10 = 1(mod 3)
= > (2^10)^2 = 1^2(mod 3)
= > 2^20 = 1(mod 3)
= > 2^20 = 1(mod 3)
= > (2^20)^5 = 1^5(mod 3)
= > 2^100 = 1(mod 3).
Therefore, the remainder is 1.
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Hope this helps!