Find the remainder when 2^35 is divided by 31?
Answers
Answered by
4
Helo mate here your ans
3 is the remainder when 2^{35}2
35
divided by 5.
Given:
2^{35}2
35
divided by 5
To find:
Remainder = ?
Solution:
To find the remainder of2^{35},2
35
,
Let us reconstruct the power of 2 in such a way that it is easy to solve, now as we can see that the power of 2 is 35, so to easily solve the division we are going to deconstruct the power 35 into (4 / 8 + 3)(4×8+3) which means dividing
Answered by
1
Answer:
Remainder when 2^35 is divided by 31 is 0 as 2^35 = 34359738368 and when we divide it by 31, it completely divides it on 1108378657
Therefore, remainder is zero
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