Math, asked by Anuvichu, 11 months ago

find the remainder when 2 ^81 is divided by 17​

Answers

Answered by aquialaska
4

Answer:

Remainder is 2.

Step-by-step explanation:

Given numbers are 2^{81} and 17.

To find: Remainder when 2^{81} divisible by 17.

We know that 2 has cyclicity of 4.

So, we can write given number as,

2^{80}\times2

(2^4)^{20}\times2

\imples(16)^{20}\times2

         

We also know that

When 16 is divided by 17 it leave -1 as remainder,

So,

\implies(-1)^{20}\times2

\implies1\times2

⇒ 2

So, when 2 is divided by 17 it leaves remainder = 2.

Therefore, Remainder is 2.

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