Math, asked by skmathin2000, 8 months ago

find the remainder when 2 power 2013 is divided by 17 ​

Answers

Answered by nick114577
3

Answer:

2383628.8823529

Step-by-step explanation:

this your answer

Answered by codiepienagoya
9

Given:

\bold{\frac{2^{2013}}{17}}

To prove:

Find the remainder.

Solution:

\Rightarrow  \bold{\frac{2^{2013}}{17}}\\\\

As we know,

= 2^1 = 2\\\ = 2^2 =4\\\ = 2^3 =8\\.\\.\\.\\.\\\ So, \ = 2^{2013} can be written as:

= \ 2^{2012 \times 2 }

= ((2)^{4})^{504} \\\\ = 16^{504}

= \frac{16^{504} \times 2 }{17}\\\\= \frac {(16^{504}) \times 2 }{17}}\\\\= (-1)^{504} \times 2 \\\\= 1\times 2 \\\\  = 2

The remainder to the given value is = 2.

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