Find The Remainder When 2 X Cube Minus 3 X Square + 7 X Minus 8 Is Divided By X Minus One?
Answers
Answered by
19
Answer:
-2
Step-by-step explanation:
let x-1 be x=1
now substitute
2(1)^3–3(1)^2+7(1)–8
2–3+7–8
2–3–1
2–4
–2
Answered by
2
- Step-by-step explanation:
- (2x^3 - 3x^2 + 7x - 8) ÷ x
- x(2x^2 - 3x + 7)/x -8/x
- 2x^2 - 3x + 7 - 8/x
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