find the remainder when 2222^(5555)+5555^(2222) is divided by 7
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Answer:
(16)1111+(243)1111 is completely divisible by 7. Hence (5555)2222+(2222)5555 is completely divisible by 7 leaving remainder zero. So the remainder when (5555)2222+(2222)5555 is divisible by 7 is zero.
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Answer:
We all know 259 is a multiple of 7. Therefore (16)1111+(243)1111 is completely divisible by 7. Hence (5555)2222+(2222)5555 is completely divisible by 7 leaving remainder zero. So the remainder when (5555)2222+(2222)5555 is divisible by 7 is zero.
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