find the remainder when 2x^2-3x+5 is divided by 2x-3.
utkarshkumarsipcbezi:
05
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Hey there!
2x - 3
Let us take this equation is equivalent to zero
2x - 3 = 0
2x = 3
x = 3 ÷ 2
Now, substitute the value of x and the number left at last is the remainder, this is called the remainder theorem
2x² - 3x + 5
2 ( 3 ÷ 2 )² - 3 ( 3 ÷ 2 ) + 5
2 ( 9 ÷ 4 ) - ( 9 ÷ 2 ) + 5
( 9 ÷ 2 ) - ( 9 ÷ 2 ) + 5
LCM = 2
( 9 - 9 + 10 ) ÷ 2
10 ÷ 2
= 5
The remainder is 5
Hope my answer helps!
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Answered by
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Hence, The remainder is 5
HOPE it helps to you!!!
HOPE it helps to you!!!
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