Find the remainder when 2x^2+4x+5x+10 is divided by x+2.
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Equation=>2x^2+4x+5x+10
=>2x^2+9x+10
Divisor=>(x+2).
So 2x^2+9x+10 is divided by (x+2),the quotient is (2x+5) and the remainder is 0.
Which means (x+2) is a factor of the equation 2x^2+9x+10 hence x=-2 is one root of the equation.
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