find the remainder when 2x^3+3x^2+4x+7 is divided by X +3
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Answer:
Given
f(x)=2x
3
−3x
2
+4x+7
Consider x−2=0⇒x=2
By remainder theorem, When f(x) is divided by (x−2)
Remainder r=f(2)
=2(2)
3
−3(2)
2
+4(2)+7
=16−12+8+7
=31−12
=19
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