Math, asked by akshayiv27, 3 months ago

find the remainder when 2x^3+3x^2-5x+7 is divided by x-1​

Answers

Answered by ansivaparvathi993
1

Answer:

The Remainder is 7.

Step-by-step explanation:

The remainder is 7 .

is it okay .☺

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Answered by shrabantijana5811
0

Answer:

let,

f(x)=2x^3+3x^2-5x+7

the remainder when 2x^3+3x^2-5x+7 is divided by x-1

is f(1).[since x-1=0 or,x=1]

f(1)=2(1)^3+3(1)^2-5(1)+7=2+3-5+7=7

the reminder is 7.

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