find the remainder when 2x^3+3x^2-5x+7 is divided by x-1
Answers
Answered by
1
Answer:
The Remainder is 7.
Step-by-step explanation:
The remainder is 7 .
is it okay .☺
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Answered by
0
Answer:
let,
f(x)=2x^3+3x^2-5x+7
the remainder when 2x^3+3x^2-5x+7 is divided by x-1
is f(1).[since x-1=0 or,x=1]
f(1)=2(1)^3+3(1)^2-5(1)+7=2+3-5+7=7
the reminder is 7.
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