Question

Find the remainder, when 2x^3 - 3x^3 +7x - 8 is dividend by x -1.​

Answer 1

Heya!!

Here's your answer!!

Let f(x) = 2x³ - 3x² + 7x - 8 .....(i)

Since, f(x) is divided by x-1, therefore we have to find the value of f(1).

therefore,

f(1) = 2(1)³ -3(1)² + 7(1) - 8

= 2 - 3 + 7 - 8

= 9 - 11

= -2

Hence, the required remainder is -2.

Glad help you,

it helps you,

thanks.

Answer 2

Answer:

p(x)=2x³–3x³+7x–8 or –x³+7x–8

g(x)=x–1=0

so, x=1

Now, substituting "1" for 'x';

p(1)=–(1)³+7(1)–8

=–1+7–8

p(1)= –2 is the remainder.

When, p(x)=2x³–3x²+7x–8

so, p(1)=2(1)³–3(1)²+7(1)–8

=2–3+7–8

=–1–1

= –2 is the remainder