Question

Find the remainder when 2x^3-4x+7 divided by x+1

Answer 1

$<b>$Answer:

$let \: \: 2 {x}^{3} - 4x + 7 = f(x) \\ and \: \: x + 1 = p(x) \\ \\ = > x + 1 = 0 \\ \\ = > x = - 1 \\ \\ f(x) = 2 {x}^{3} - 4x + 7 \\ \\ f( - 1) = 2 {( - 1)}^{3} - 4( - 1) + 7 \\ \\ f( - 1) = - 2 + 4 + 7 \\ \\ f( - 1) = 2 + 7 \\ \\ f( - 1) = 9$

Tysm for the question!

Answer 2

$\tt \large AHOY!!! \:$

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$x + 1 = 0 \\ \\ x = -1 \\ \\ Put \: the \:value \:of\: x\: in \:given\: polynomial \\ \\ p (x) = {2x}^{3} - 4x + 7 \\ \\ p (-1) = 2{(-1)}^{3} - 4(-1) + 7 \\ \\ p(-1) = 2(-1) - 4(-1 ) + 7 \\ \\ p(-1) = - 2 + 4 + 7 \\ \\ p(-1) = - 2 + 11 \\ \\ p(-1) = 9$

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