Question

find the remainder when 2x^4+ax^3-3a^2x^2+6x is divided by (x-a) ​

Answer 1

Answer:

x-a=x=a

substitute a in form of x

then 2(a)×4+a(a)×3-3(a)×2(a)×2+6(a)

2a×4+3a-3a×2a×8a

=8a+0×16a

8a+0

=8a

8a is the remainder when x-a is divided 2x^4+ax^3-3a^2x^2+6x