Question

find the remainder when 2x cube +5x square -6x+2 is divided by x+2​

Answer 1

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

(((2 • (x3)) - 5x2) + 6x) - 2 = 0

STEP

2

:

Equation at the end of step

2

:

((2x3 - 5x2) + 6x) - 2 = 0

STEP

3

:

Checking for a perfect cube

3.1 2x3-5x2+6x-2 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 2x3-5x2+6x-2

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 6x-2

Group 2: 2x3-5x2

Pull out from each group separately :

Group 1: (3x-1) • (2)

Group 2: (2x-5) • (x2)

PLEASE MARK ME BRANALIST

Answer 2

Answer:

The remainder when 2x cube +5x square -6x+2 is divided by x+2​ is 18.

Step-by-step explanation:

Let f(x)=2x³+5x²-6x+2

f(x)=2x³+5x²-6x+2 is divided by x+2

According to remainder theorem,

when f(x) is divided by (x+2), Remainder =f(-2)

f(x)=2x³+5x²-6x+2

f(-2)= 2(-2)³+5(-2)²-6(-2)+2

       = 2(-8)+20+12+2

       =-16+20+14

       =-16+34

  f(-2) = 18

∴The remainder when 2x cube +5x square -6x+2 is divided by x+2​ is 18.