Question

Find the remainder when 2x³ + 7x² – x + 1 is divided by (x + 1)​

Answer 1

Answer:

Quotient is x^2-3x-4x2

−3x−4 and Remainder is -8.

Step-by-step explanation:

Given;

Dividend = 2x^3-7x^2-5x-42x 3 −7x 2 −5x−4

Divisor = 2x-12x−1

We need to find the quotient and remainder.

Solution:

We have attached the division for your reference.

Step 1: Now the Dividend is 2x^3-7x^2-5x-42x−7x 2

−5x−4 and Divisor is 2x-12x−1 , we will first multiply the divisor with x^22

we get 2x^3-x^22x 3 −x 2

so 2x^32x

3

gets cancelled and we get the answer as -6x^2-5x-4−6x

2

−5x−4 as remainder and Quotient as x^2x

2

.

Step 2: Now the Dividend is -6x^2-5x-4−6x

2

−5x−4 and Divisor is 2x-12x−1 , we will multiply the divisor with -3x−3x we get -6x^2+3x−6x

2

+3x so 6x^26x

2

gets cancelled and we get the answer as -8x-4−8x−4 as remainder and Quotient as x^2-3xx

2

−3x .

Step 3: Now the Dividend is -8x-4−8x−4 and Divisor is 2x-12x−1 , we will multiply the divisor with -4−4 we get -8x-4−8x−4 so 8x8x gets cancelled and we get the answer as -8−8 as remainder and Quotient as x^2-3x-4x

2

−3x−4 .

Now there is no more further division possible.

Hence the Final Answer is

Quotient is x^2-3x-4x

2

−3x−4 and Remainder is -8.