find the remainder when 2xis the power of four-3xcube-5xsquared+5 is divided by (x-2)
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2x^4-3x^3-5x^2+5 is the given equation now dividing this with (x-2 ) we have
=2x^3+x^2-3x-6 and then the remainder left is -7
=2x^3+x^2-3x-6 and then the remainder left is -7
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