Find the remainder when 3^49+ 9^49is divided by 10?
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3⁴⁹ = 3×3⁴⁸ = 3×(3²)²⁴ = 3×9²⁴
10 = 9-1
substitute x for 9 we get
3x²⁴+x⁴⁹ ÷ (x-1)
when f(x) is divided by (x-a) then remainder is f(a)
remainder= f(1) = 3+1 = 4
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