Question

find the remainder when 3 x cube minus 4 x square + 7 x minus 5 is divided by x minus 3 and X + 3

Answer 1

Let p(x) = 3x3 - 4x2 + 7x - 5 
When p(x) is divided by (x - 3) the remainder is p(3)
Put x = 3 in p(x)
p(3) = 3(3)3 - 4(3)2 + 7(3) - 5 
      = 81 - 36 + 21 - 5 = 61
Similarly try for (x + 3)

Answer 2

Answer:

Step-by-step explanation: