Question

find the remainder when 3x^2+6x-9 divided by 3x-1 by remainder theorem​

Answer 1

Answer:

Remainder = -20/3

Step-by-step explanation:

P(x) = 3x² + 6x - 9

3x - 1 = 0

⇒ x = 1 / 3  -----> (1)

Sub. (1) in P(x)

⇒ Remainder = 3 (1/3)² + 6(1/3) - 9

                       = 3/9 + 6/3 - 9

                       = 1/3 + 2 - 9

                       = 1/3 - 7

                       = 1 - 21 / 3

                       = -20/3