Question

find the remainder when 3x^3-4x^2=7x-5 is divided by(x-1)Step-by-step explanation

Answer 1

Step-by-step explanation:

just put the value of X in this equation u get urs answer perfectly

Answer 2

x-1=0

x=1

Now,We obtained the value of x.

so we will put the value of X

Given:-p(x)=3x^3-4x^2+7x-5.

Now,

3(1)^3-4(1)^2+7(1)-5=0

3-4+7-5

-1+7-5

6-5=1.