Question

Find the remainder when 3x^3-4x^2 7x-5 is divided by (x -3)

Answer 1

Answer:

x-3=0

X=0+3

X=3

p(3)=3(3)³-4(3)²+7(3)-5

p(3)= 3×27-4×9+21+5

p(3)= 81-36+26

p(3)= 81-10

p(3)= 71