Question

Find the remainder when 3x^3-6x^2 +3x-7/9 is divided by 3x-4

Answer 1

Therefore,the remainder is -3/9 or -1/3

Answer 2

The remainder will be -1/3, when 3x³ - 6x² + 3x - 7/9 is divided by 3x - 4.

We have to find the remainder when 3x³ - 6x² + 3x - 7/9 is divided by 3x - 4.

Remainder theorem :

• It is useful to find the remainder if we divides an polynomial by another lower degree polynomial.
• If a polynomial y = P(x), is divided by (x - a), then P(a) will be remainder.

here P(x) = 3x³ - 6x² + 3x - 7/9 is divided by (3x - 4).

∴ (3x - 4) = 0 ⇒x = 4/3

∴ the remainder = P(4/3)

= 3(4/3)³ - 6(4/3)² + 3(4/3) - 7/9

= 64/9 - 96/9 + 4 - 7/9

= (64 - 96 + 36 - 7)/9

= -1/3

Therefore the remainder is -1/3