Question

Find the remainder when 3x³+3x²-5x+3 is divided by x+1.​

Answer 1

Step-by-step explanation:

By remainder theorem

x+1=0

x=−1

p(x)=3x³+3x²−5x+3

p(−1)=3(-1)³+3(-1)²−5(-1)+3

=-3+3+5+3

=8

Thus, remainder is 8

Answer 2

$\huge \bold \color{aqua}{Question}$

Find the remainder when 3x³+3x²-5x+3 is divided by x+1.

$\huge \bold \color{aqua}{Explaination}$

$\bold \color{red}{By \: Remainder \: Theorem:}$

First, we have to find the value of $x$

$x \: + \: 1 \: = \: 0$

$x \: = \: 0 \: - \: 1$

$x \: = \: -1$

Now, By putting the value of $x$ in the given equation:-

$\implies$ $3x^3 \: + \: 3x^2 \: - \: 5x \: + \: 3$

$\implies$ $3 (-1)^3 \: + \: 3 (-1)^2 \: - \: 5 (-1) \: + \: 3$

$\implies$ $3 (-1) \: + \: 3 \: + \: 5 \: + \: 3$

$\implies$ $-3 \: + \: 3 \: + \: 5 \: + \: 3$

$\implies$ $8$

Hope it helps you.

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