Math, asked by keziashohe, 2 months ago

find the remainder when 3x⁴+24x³-7x²-10x +6 is divided by 2x + 5​

Answers

Answered by alkabenjayeshpatel
1

Answer:

2x + 5 = 0

2x = - 5

x = - 5 / 2

p(x) = 3 {x}^{4}  + 24 {x}^{3}  - 7 {x}^{2}  - 10x + 6 \\  \\ p(  -  \frac{5}{2} ) = 3 ({ -  \frac{5}{2}) \: }^{4}  + 24( {  - \frac{5}{2}) }^{2}  + 7( {  - \frac{5}{2}) }^{2}  - 10( -  \frac{5}{2} ) + 6 \\  \\ 3 \times  - \frac{625}{16}  + 24 \times  -  \frac{25}{4}  - ( -  \frac{50}{2} ) + 6 \\  \\  -  \frac{1875}{16}   -  \frac{600}{4}  + 25 + 6 \\  \\  -  \frac{1875}{16}  - 150 + 31 \\  \\  -  \frac{1875}{16}  - 119 \\  \\  \frac{ - 1875 - 1904}{16}  \\  \\  \frac{ - 3779}{16}

Hope it helps to you!!

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