find the remainder when 3xcube minus4xsquare plus 7xminus5is divided by xminus1
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3x cubes - 4x cubes = -1x cubes
-1x cubes + 7x cubes = 8x cubes
8x cubes - 5x cubes = 3x cubes
3x divided by 1x cubes is 3x cubes.
Hope you understand! ;D
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if (x-1) was the factor of (3x^3-4x^2+7x-5) it would have satisfy the equation bt becoz it's not a factor so it will not satisfy the equation and putting x=1 we can find the remainder-
= 3×(1)^3 - 4×(1)^2 + 7×(1) - 5
= 3 - 4 +7 - 5
=1 ans
= 3×(1)^3 - 4×(1)^2 + 7×(1) - 5
= 3 - 4 +7 - 5
=1 ans
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