Math, asked by smiley143, 1 year ago

Find the remainder when 43^33 - 23 ^33 is divided by 5

Answers

Answered by mysticd
52
Hi ,

************************************************************************************
The expression a^n - b^n is always divisible by ( a - b ) , if n is any

positive integer.

*************************************************************************************

By useing above divisibility concept ,

43^33 - 23^33 is divisible by ( 43 - 23 )

i.e ( 43 - 23 ) = 20

Therefore ,

20 is one factor of 43^33 - 23^33

20 is divisble by 5.

5 is factor of 43^33 - 23^33

By this we conclude that

When 43^33 - 23 ^33 is divided by 5 the remainder is zero.

I hope this helps you.

*****

Answered by kanishkj09
3

Answer:

Step-by-step explanation:

Hi ,

************************************************************************************

The expression a^n - b^n is always divisible by ( a - b ) , if n is any

positive integer.

*************************************************************************************

By useing above divisibility concept ,

43^33 - 23^33 is divisible by ( 43 - 23 )

i.e ( 43 - 23 ) = 20

Therefore ,

20 is one factor of 43^33 - 23^33

20 is divisble by 5.

5 is factor of 43^33 - 23^33

By this we conclude that

When 43^33 - 23 ^33 is divided by 5 the remainder is zero.

I hope this helps you.

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