Question

Find the remainder when 4x^3 - 12 x^2 + 14 x - 3 is divided by (2x - 1)

Answer 1

$\huge\mathfrak{Answer:}$

Given:

We have been given a cubic polynomial

(4x³ - 12x² + 14x - 3).

To Find:

We need to find the remainder when

(4x³  - 12x² + 14x - 3) is divided by (2x - 1).

Solution:

When we divide (4x³  - 12x² + 14x - 3) by (2x - 1), we get remainder as (19x - 3).

$\boxed{\begin{array}\quad\begin{tabular}{m{3.5em}cccc}&& 2x^2& + 5x\\\cline{1-6}\multicolumn{2}{l}{2x - 1\big)}&4x^3&-12x^2& +14x& - 3\\&& - (4x^3&-2x^2)&&\\\cline{3-4}&&&10x^2& + 14x& - 3\\&&& - (10x^2& - 5x)&\\\cline{4-6}&&&& 19x& - 3\\\end{tabular}\end{array}}$

Answer 2

Your answer refer to the attachment.