find the remainder when 4x^3-3x^2+4x+2 divide (a)x-1 and(b) x-2
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Answer:
Let p(x) = 4x³ - 3x² + 4x -2
(a)
Let x-1 = 0
x = 1
Remainder theorem,
p(1) = 4(1)³ - 3(1)² + 4(1) - 2
= 4 - 3 + 4 -2
=3
So, R = 3
(b)
Let x-2 = 0, x= 2
p(2) = 4(2)³ -3(2)² + 4(2) -2
= 32 - 12 + 8 -2
= 26
So, remainder is 26
Hope this helps!
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