Find the remainder when 4x ^ 3 - 3x ^ 2 + 4x - 2 is divided by (i) x + 2 (i) x + 1/2
Answers
Answered by
14
Answer:
Let p(x) = 4x³ - 3x² + 4x -2
(a)
Let x-1 = 0
x = 1
Remainder theorem,
p(1) = 4(1)³ - 3(1)² + 4(1) - 2
= 4 - 3 + 4 -2
=3
So, R = 3
(b)
Let x-2 = 0, x= 2
p(2) = 4(2)³ -3(2)² + 4(2) -2
= 32 - 12 + 8 -2
= 26
So, remainder is 26
Hope this helps!
Answered by
0
Answer:
Part 1:−
x−1)
4x
3
−3x
2
+4x−2
(4x
2
+x+5
4x
3
−4x
2
−+
_____________________
x
2
+4x
x
2
−x
−+
_____________________
5x−2
5x−5
−+
_____________________
3Remainder.
Part 2:−
x−2)
4x
3
−3x
2
+4x−2
(4x
2
+5x+14
4x
3
−8x
2
−+
_____________________
5x
2
+4x
5x
2
−10x
−+
_____________________
14x−2
14x−28
−+
_____________________
26Remainder.
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