Question

find the remainder when 4x3+4x2+5x-3 is divided by x-3​

Answer 1

Answer:

Hope it helps....... xD

Answer 2

Answer:-

→156=r(remainder

$\rule{200}{1}$

Explanation:-

As we know p(x) and q(x)

[°•° p(x)=4x³+4x²+5x-3]

[°•° q(x)=x-3]

→p(x)=q(x)×g(x)+r(x)

→$\frac{p(x)}{q(x)}$=g(x)+r(x)

→$\frac{4x^{3}+4x^{2}+5x-3}{x-3}$=g(x)+r(x)

→g(x)=4x²+16x+53

→r(x)=156

★Refer Attachment For Division★

$\rule{200}{8}$