Question

Find the remainder when 5x^3 - x^2 + 6x - 2 is divided by 1 - 5x

Answer 1

$\sf \purple{p(x) = 1 - 5x = 0} \\ \sf{5x = 0 + 1} \\ \sf{5x = 1} \\ \sf \therefore \pink{x = \frac{1}{5} }$

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$\sf \purple{g(x) = {5x}^{3} - {x}^{2} + 6x - 2 } \\ \rightarrow \sf{5 {( \frac{1}{5} )}^{3} - { (\frac{1}{5}) }^{2} + 6 \times \frac{1}{5} - 2 } \\ \rightarrow \sf{5 \times \frac{1}{125} - \frac{1}{25} + \frac{6}{5} - 2 } \\ \rightarrow \sf{ \cancel5 \times \frac{1}{ \cancel125} - \frac{1}{25} + \frac{6}{5} - 2 } \\ \rightarrow \sf{ \cancel\frac{1}{25} - \cancel \frac{1}{25} + \frac{6}{5} - 2 } \\ \rightarrow \sf{ \frac{6}{5} - \frac{2}{1} } \\ \rightarrow \sf{ \frac{6 - 10}{5} } \\ \rightarrow \sf \red{ - \frac { 4}{5} }$

Answer 2

ꜱᴇᴇ ᴛʜᴇ ᴩɪᴄ ᴛʜᴇʀᴇ ɪꜱ yᴏᴜʀ ᴀɴꜱᴡᴇʀ ꜰᴏʀ yᴏᴜʀ qᴜᴇꜱᴛɪᴏɴ .......,.......