Question

find the remainder when 81(64^25)is divided by 9^4

Answer 1

Hi there

Your answer is :-

$81 ( 64 ^{25} )\div 9^4$

$\frac{81\times64 ^{25}}{9^4}$

$\frac{9^2\times64 ^{25}}{9^4}$

$\frac{64 ^{25}}{9^2}$

$\frac{64 ^{25}}{81} ( Ans )$

$1.76203\times10^{43}( Alternative Answer )$


Thank You