Math, asked by Maajid5213, 1 year ago

Find the remainder when 83^261is divided by 17

Answers

Answered by DevendraLal
2

Given:

83^261is divided by 17.

To find:

The remainder when 83^261is divided by 17.

Solution:

1) We will solve this by the remainder theorem.

2) We will represent 83 as the nearest multiple of the 17.

  • 83 can be written as 85-2

so the remainder is given by:

  • \frac{(85-2)^{261}}{17}

3) 85 is the multiple of 17 so this will give you the remainder zero so the term will be:

  • \frac{-2^{261}}{17}
  • \frac{-2^{260}.-2^{1}}{17}
  • \frac{{(-2^{4})}^{65}.-2^{1}}{17}
  • \frac{{16}^{65}.-2^{1}}{17}

now 16 is represented as multiple of 17

  • \frac{{(17-1)}^{65}.-2^{1}}{17}
  • \frac{{(-1)}^{65}.-2^{1}}{17}
  • \frac{{-1}.-2}{17}
  • \frac{2}{17}

The numerator is less than the denominator so the remainder is the given numerator of the fraction only.

The remainder when 83^261is divided by 17 is 2

Answered by py170686
0

Answer:

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Step-by-step explanation:

Given:

83^261is divided by 17.

To find:

The remainder when 83^261is divided by 17.

Solution:

1) We will solve this by the remainder theorem.

2) We will represent 83 as the nearest multiple of the 17.

83 can be written as 85-2

so the remainder is given by:

3) 85 is the multiple of 17 so this will give you the remainder zero so the term will be:

now 16 is represented as multiple of 17

The numerator is less than the denominator so the remainder is the given numerator of the fraction only.

The remainder when 83^261is divided by 17 is 2

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