Find the remainder when( 888..repeat 63 times) is divided by 9
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888.....63 times/ 9
Divisibility by 9:
If sum of digits is divisible by 9, then the number is divisible by '9'
88...63 times= Sum of digits = 8*63
Sum/9 = 8*63/9== perfectly divisible by '9'
Hence Remainder = 0
Hope it helps.
Divisibility by 9:
If sum of digits is divisible by 9, then the number is divisible by '9'
88...63 times= Sum of digits = 8*63
Sum/9 = 8*63/9== perfectly divisible by '9'
Hence Remainder = 0
Hope it helps.
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