Question

Find the remainder when 9x^3+9x^2-19x+12 is divided by 3x-1

Answer 1

Answer:

$\frac{9 {x}^{3} + 9 {x}^{2} - 19x + 12 }{3x - 1}$

remainder =

$7$

Hope this helped u...

Answer 2

Answer:

3x-1 | 9x³+9x²-19x+12 | steps:

- 9x³ +3x | 1. 9x³/3x= 3x²

________________ 3x²(3x-1)=9x³-3x²

12x²-19x 2. 12x²/3x=4x

-12x²+4x 4x(3x-1)=12x²-4x

________________ 3. 15x²/3x=(-5)

-15x+12 (-5)(3x-1)=(-15x +5)

+ 15x - 5

________________

7

therfore,

Quotient = 3x²+4x-5

Remainder = 7