find the remainder when 9x²-3x²+x-5 is divided by x-2/3
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Given, polynomial 9x^2 - 3x^2 + x - 5 divided by x - 23 .Then divided by x - 23 so x - 23 = 0 or x = 23 .Replace x by 23 , we get, p(x) = 9x^3 - 3x^2 +
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