Question

find the remainder when 9x³-3x²+x-5 is divided by x⅔​

Answer 1

Answer:

f(x) = 9x³-3x²+x-5

f(x⅔) =9× (x³)⅔ - 3×(x²)⅔ +x⅔-5

$9 \times {x}^{3 \times \frac{2}{3} } - 3 \times {x}^{2 \frac{2}{3} } + {x}^{ \frac{2}{3} } - 5$

$9 {x}^{2} - 3 {x}^{ \frac{4}{3} } + {x}^{ \frac{2}{3} } - 5$

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