Find the remainder when 9x3-3x2+x-5 is divided by x-2 /3
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Given, polynomial 9x² - 3x² + x - 5 divided by
2 3 X
Then divided by x SO X 3 23 2 3 = 0 or x
2 3' Replace x by we get,
p(x) = 9x ^ 3 - 3x ^ 2 + x - 5
p(2/3) = 9 * (2/3) ^ 3 - 3 * (2/3) ^ 2 + (2/3) - 5
2
3
P
8
4 2
= 9x - 3 x + - 5
27
9 3
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P 2130 72 27 12 + 9 3 ст
P 23 7236 +18 - 135 27 -81 27 = -3.
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