Find the remainder when 9x3 square 2-3xsquare +x-5 is divide by x-1/2 by long division method
Answers
Answered by
0
Answer:
By Remainder Theorem,
x = \frac{2}{3}x=32
Hence,
\begin{gathered} = > 9 {( \frac{2}{3}) }^{3} - 3 {( \frac{2}{3} )}^{2} + \frac{2}{3} + 5 = r \\ \\ \\ = > 9( \frac{8}{27} ) - 3(\frac{4}{9} ) + \frac{2}{3} - 5 = r \\ \\ \\ = > \frac{8}{3} - \frac{4}{3} + \frac{2}{3} - 5 = r \\ \\ \\ = > \frac{8 - 4 + 2 - 15}{3} = r \\ \\ \\ = > - \frac{9}{3} = r \\ \\ \\ = > - 3 = r\end{gathered}=>9(32)3−3(32)2+32+5=r=>9(278)−3(94)+32−5=r=>38−34+32−5=r=>38−4+2−15=r=>−39=r=>−3=r
Hence, remainder is –3
Answered by
0
Step-by-step explanation:
please mark me as brainlist
Attachments:
Similar questions