Find the remainder when f(x) = x 3 - 3x + 1 is divided by (2 - 3x).
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2-3x = 0
3x = 2
x = 2/3
f(2/3) = (2/3)^3 - 3(2/3) + 1
= (8/27) - 2 + 1
= 8/27 - 1
= -18/27
3x = 2
x = 2/3
f(2/3) = (2/3)^3 - 3(2/3) + 1
= (8/27) - 2 + 1
= 8/27 - 1
= -18/27
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