Find the remainder when f(x)=x^3-6x^2+2x is divided by g(x)1-3x
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1/27
Step-by-step explanation:
f(x)=x^3-6x^2+2x
g(x)=0
given g(x) = 1-3x
1-3x=0
x=1/3
substitute the value of x in f(x)
f(x)=(1/3)^3-6(1/3)^2+2(1/3)
1/27-6/9+2/3
1/27-2/3+2/3
=1/27
i hope so this answer is Right
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