Question

Find the remainder when f(x)=x^4-3x^2+4 is divided by g(x)=x-2 And verify the result by actual division.​

Answer 1

Step-by-step explanation:

f(x)= x^4-3x^2+4

g(x)= x-2

= x=2

f(2)= (2)^4-3(2)^2+4

= 16-12+4= 4+4=8

So, 8 is the remainder of p(x).

I think u Understand the answer.