Question

Find the remainder when f(x) = x⁴-3x²+ 4 is divided by g(x) = (x-2)​

Answer 1

here is your answer......

Answer 2

Answer:

$\huge\mathfrak\red{Hello~Army}$

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$f(x) = {x}^{4} - 3 {x}^{2} + 4$

$g(x) = (x - 2)$

$x - 2 = 0$

--------------------(using remainder theorem)

$\boxed{{x = 2}}$

$= {x}^{4} - 3 {x}^{2} + 4$

$= {(2)}^{4} - 3 {(2)}^{2} + 4$

$= 16 - 12 + 4$

$= 4 + 4$

$= 8$

Therefore, remainder is 8.

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