Find the remainder when f(x) = x4
– 3x3
+ 12x2
– 14x + 1 is divided by (x – 3).
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According to remainder theorem, We know if f(x) is divided by ( x - a) , then remainder = f(a) ,
If f(x) is divided by (x-a) we have taken it (x -a) = 0 .So, Remainder would be f(a) .
Now, p(x) = 4x³ -12x²+14x - 3 .
If p(x) is divided by 2x-1 , then (2x-1) = 0 , x = 1/2 .So when p(x) is divided by (2x-1) , it leaves a remainder p(1/2)
p(1/2)
= 4(1/2)³ -12(1/2)²+14(1/2)-3
= 4(⅛)-12(1/4)+7-3
= 1/2 -3 + 7 - 3
= 1/2 +1
= 3/2
The remainder when 4x³-12x²+14x-3 divided by 2x-1 is 3/2
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