Question

find the remainder when (n^2+n+41)^2 is divided by 12​

Answer 1

Step-by-step explanation:

(n^2+n+41)^2 ??????????????

Answer 2

Answer:

ans is 1

first put n=1...we get1849/12.remainder will be 1...again put n=2...we get2209/12...remainder will be again put n=3,4,5...the last term of numerator will be always 9...if they divide by 12 we always get 1 remainder